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3927 · Food for Thought

Is 3927 harder than 2048?

A state-space showdown between a flat grid of twos and a cube built entirely out of threes.

01 · Two oceans

The question sounds simple. Counting the answer is not.

Both games are sliding-number puzzles. In 2048 you shove a 4×4 grid of sixteen cells in one of four directions; equal tiles collide and double, climbing the powers of two. In 3927 you shove a 3×3×3 cube of twenty-seven cells in one of six directions; three equal blocks collide and triple, climbing the powers of three, 3, 9, 27, the very digits of the name.1 To ask which is harder is really to ask which game hides the bigger ocean of possible positions. So let us try to measure the water.

02 · The exponent

Cells matter more than the number system does.

A board's raw size grows as (symbols per cell)cells. The count of cells sits in the exponent, which is where all the leverage lives. 2048 offers sixteen cells; 3927 offers twenty-seven. Hold the per-cell alphabet fixed and the cube is already larger by a factor of roughly a27−16 = a11, with an alphabet of ten symbols, that alone is a hundred billion times more states before we account for anything else. The extra dimension, not the base-3 arithmetic, is the real engine.

03 · The alphabet

What a single cell can say.

Each cell is either empty or holds one tile value. For 2048 capped at the 256 tile, a cell speaks one of nine symbols, empty, plus {2, 4, 8, 16, 32, 64, 128, 256}. A published upper bound built from exactly this alphabet puts the 4×4 board at about 5.63 × 1014 positions, and the authors are candid that this ceiling includes illegal boards that can never actually occur.2 Give 3927 a comparable depth, empty plus {3, 9, 27, 81, 243, 729, 2187}, eight symbols, and its raw ceiling is 827 ≈ 2.4 × 1024. Base 3 buys 3927 fewer symbols per cell than base 2 would; the eleven extra cells hand it back the sky.

Slide the value ladders a little deeper and 3927's ceiling outruns 2048's by somewhere between a billion and a hundred billion fold. The cube wins on the exponent.

04 · The tally

Ceilings, and the few exact counts we have.

Nobody has enumerated the reachable states of full-size 2048, let alone 3927. But researchers have exhaustively solved shrunken 2048 boards, and those exact figures anchor our estimates. A 3×3 board of 2048 holds 48,713,519 reachable states; stretch it to 4×3 and the count leaps past a trillion, 1,152,817,492,752 states, with 739,648,886,170 distinct after-move positions.3 Each added cell multiplies the world. Extrapolate that curve to 27 cells and no honest table can print a single number.

Combinatorial face-off, estimates and upper bounds, not exact counts
Property20483927
Board4×4 flat3×3×3 cube
Cells1627
Number base23
Merge rule2 alike → double3 alike → triple
Shift directions46
Symbols / cell (matched depth)98
Raw ceiling (incl. illegal)~1.9 × 10¹⁵~2.4 × 10²⁴
Cited refined upper bound5.63 × 10¹⁴none published
Exact count, 4×3 sub-board1.15 × 10¹²,

A note on honesty

Every big number here is an upper bound or an order-of-magnitude estimate, never a census. The ceilings count boards that legal play can never reach, three lone 2s, say, or values that no merge sequence can produce. The 2048 figures are drawn from peer-reviewed work; the 3927 figures are my own back-of-envelope ceilings, computed the same way, and should be read as "no smaller than this, probably far less." The rules of both games are measured from the game's design documents, not assumed.

05 · Branching

How wide is a single move?

State-space size is the map; branching factor is how fast you walk it. On each turn the player picks a direction, up to four in 2048, up to six in 3927, so the cube offers fifty percent more real choices per move. Then chance intervenes: the game drops a new tile into a random empty cell. 2048 spawns a 2 or a 4, roughly two outcomes per open cell across as many as fifteen empties; 3927 always spawns a single 3, but into as many as twenty-six empties.1 Multiply decision by chance and the game tree of 3927 fans out wider at every ply, and, because merges of three are rarer than merges of two, its runs tend to last longer, deepening the tree as well as widening it.

06 · Verdict

By the only measure we can count, yes.

"Harder" for a human is a matter of feel, and 2048 is no pushover, deciding whether an arbitrary position can reach a target tile is provably NP-hard on a general board.4 But as a combinatorial object, 3927 is the larger animal by a wide, honest margin: more cells in the exponent, more directions in the branching, longer games in the depth. The base-3 arithmetic that gives it its name is almost a red herring. The difficulty was never in the threes. It was in the third dimension.

Sources & method

  1. Rules of 3927 and 2048, board dimensions, merge rules, shift directions, and tile-spawn behavior, measured from the game's design documents.
  2. Alexey Slizkov, Computational bounds for the 2048 game (2023). Gives an upper bound of ~5.63×10¹⁴ positions for the 4×4 board at tile cap 256, explicitly including illegal positions. arxiv.org/abs/2303.07266
  3. Tomoyuki Kaneko & Shuhei Yamashita, Strongly Solving 20484×3 (2025). Exact reachable-state counts: 48,713,519 for 3×3 and 1,152,817,492,752 for 4×3 (739,648,886,170 afterstates). arxiv.org/abs/2510.04580
  4. Stefan Langerman & Yushi Uno, Threes!, Fives, 1024!, and 2048 are Hard, FUN 2016. Proves NP-hardness of 2048-type games on an m×n board. arxiv.org/abs/1505.04274

Method: per-cell alphabet counts and the ceilings 916 and 827 are elementary combinatorics on matched value-ladder depths; the 2048 refined bound and exact sub-board counts are quoted from the cited papers. All 3927 figures are the author's estimates computed by the same recipe and are upper bounds, not enumerations. Where the two games' possibility spaces are compared, ratios are stated as ranges to reflect that uncertainty.

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